Question:
In a single slider crank mechanism, crank AB = 20 mm and connecting rod BC = 80 mm. Crank AB rotates with uniform speed of 1000 rpm in anticlockwise direction. Find
(i) angular velocity of connecting rod BC and
(ii) Velocity of slider C when crank AB makes angle of 60° with the horizontal.
Answer:
Given: Crank AB = 20 mm = 0.02 m, C. R. BC = 80 mm = 0.08 m
N = 1000 rpm, ωBA= 2πN/60 = 2π x 1000/60 = 104.7 rad/sec
VBA = ωBA x AB = 104.7 x 0.02 = 2.09 m/s
From velocty diagram: Velocity of C w.r.t. B -
VCB = vector cb = 1.15 m/s
Angular velocity of Connecting rod ‘BC’ ωCB = VCB / CB = 1.15/0.08 = 14.375 rad /sec
Velocity of slider ‘C’
VC= vector ac = 2 m/sec